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Newsgroups: sci.electronics.design
From: John Larkin <jjlar...@highNOTlandTHIStechnologyPART.com>
Date: Fri, 04 Jul 2008 18:06:10 -0700
Local: Sat, Jul 5 2008 6:06 am
Subject: Re: Feedback for low frequency PWM regulator
On Fri, 04 Jul 2008 20:44:37 GMT, "JMini"
<j.minih...@minihane.tzo.com> wrote: I guess the real question is, why? The light output will still be very >I'm building a PWM regulator for an incandescent bulb. Some of thos was >described in a thread called "RMS Approximation of PWM/Square wave". In any >case. Since there is no inductor/diode/cepacitor in the output stage I'll be >using an RMS converter (LTC1968). For the PWM section I'm using the MIC1557 >(SOT-23 size 555 equiv) for a R-C sawtooth to a comparator (TLV7211a) >inverting input. I can choose the frequency (probably in the 200-800Hz >range). The feedback is sent through the LTC1968 RMS converter to the FB pin >(0.8V) of a tiny (SC-70) 5mA voltage regulator (OnSemi NCP102). It's really >just a powerful error amplifier. The Output of that is sent to the >non-inverting input of the comparator. So if the feedback voltage drops, the >NCP102 increases voltage ot the non-inverting input of the TLV7211, thus >increasing duty cycle. I've tested this type of layout on breadboard using >different components. I got to thinking though. >Question: >Would it be possible to use a resistor divider between the MIC1557 and >comparator to reduce the voltage of the sawtooth and feed it to the >NON-inverting comparator input and send the RMS converter output directly to >the INVERTING input of the comparator? That way, a falling output voltage >would cause a reduction in voltage to the INVERTING input and increase duty >cycle? I could reduce the component count. >I realize there is no true reference voltage in the system, but since the >1557 is fed from a fixed 5V source, the sawtooth would be a constant 5*1/3 to >5*2/3 V. Thoughts guys? nonlinear on any control input. Why not feedback on the light? John You must Sign in before you can post messages.
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