Google Groups Home
Help | Sign in
Message from discussion Feedback for low frequency PWM regulator
The group you are posting to is a Usenet group. Messages posted to this group will make your email address visible to anyone on the Internet.
Your reply message has not been sent.
Your post was successful
 
From:
To:
Cc:
Followup To:
Add Cc | Add Followup-to | Edit Subject
Subject:
Validation:
For verification purposes please type the characters you see in the picture below or the numbers you hear by clicking the accessibility icon. Listen and type the numbers you hear
 
JMini  
View profile
 More options Jul 5 2008, 1:44 am
Newsgroups: sci.electronics.design
From: "JMini" <j.minih...@minihane.tzo.com>
Date: Fri, 04 Jul 2008 20:44:37 GMT
Local: Sat, Jul 5 2008 1:44 am
Subject: Feedback for low frequency PWM regulator
I'm building a PWM regulator for an incandescent bulb. Some of thos was
described in a thread called "RMS Approximation of PWM/Square wave". In any
case. Since there is no inductor/diode/cepacitor in the output stage I'll be
using an RMS converter (LTC1968). For the PWM section I'm using the MIC1557
(SOT-23 size 555 equiv) for a R-C sawtooth to a comparator (TLV7211a)
inverting input. I can choose the frequency (probably in the 200-800Hz
range). The feedback is sent through the LTC1968 RMS converter to the FB pin
(0.8V) of a tiny (SC-70) 5mA voltage regulator (OnSemi NCP102). It's really
just a powerful error amplifier. The Output of that is sent to the
non-inverting input of the comparator. So if the feedback voltage drops, the
NCP102 increases voltage ot the non-inverting input of the TLV7211, thus
increasing duty cycle. I've tested this type of layout on breadboard using
different components. I got to thinking though.
Question:
Would it be possible to use a resistor divider between the MIC1557 and
comparator to reduce the voltage of the sawtooth and feed it to the
NON-inverting comparator input and send the RMS converter output directly to
the INVERTING input of the comparator? That way, a falling output voltage
would cause a reduction in voltage to the INVERTING input and increase duty
cycle? I could reduce the component count.
I realize there is no true reference voltage in the system, but since the
1557 is fed from a fixed 5V source, the sawtooth would be a constant 5*1/3 to
5*2/3 V. Thoughts guys?

    Reply to author    Forward  
You must Sign in before you can post messages.
To post a message you must first join this group.
Please update your nickname on the subscription settings page before posting.
You do not have the permission required to post.

Create a group - Google Groups - Google Home - Terms of Service - Privacy Policy
©2009 Google